ss: Drop silly assignment
An expression of the form '(a | b) & b' will evaluate to the value of b for any value of a or b. Signed-off-by: Phil Sutter <phil@nwl.cc>
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@ -267,7 +267,7 @@ static void filter_default_dbs(struct filter *f)
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static void filter_states_set(struct filter *f, int states)
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static void filter_states_set(struct filter *f, int states)
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{
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{
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if (states)
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if (states)
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f->states = (f->states | states) & states;
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f->states = states;
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}
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}
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static void filter_merge_defaults(struct filter *f)
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static void filter_merge_defaults(struct filter *f)
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